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Proof step 9 from proof div-def-01 (previous step)

0 < j, 0 < j0 ⊦ i0 = 0, rational(0, 1) / rational(i0, j0) = rational(0, 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ ri / rj = rational(ri.num * rj.denom, ri.denom * rj.num)
Proof step 11:
0 < j, 0 < j0 ⊦ i0 = 0, rational(rational(0, 1).num * rational(i0, j0).denom, rational(0, 1).denom * rational(i0, j0).num) = rational(0, 1)

Rule argument

name: div-def rotate: F subst: [rj, ri] → [rational(i0, j0), rational(0, 1)]

Additional information

Used terms: rational(i0, j0), rational(0, 1)