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Proof step 1 from proof elim-sub (conclusion)

⊦ ri0 = ri - rj ↔ ri = ri0 + rj

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ ∃ i, j. ri = rational(i, j) ∧ 0 < j
Proof step 3:
∃ i, j. ri = rational(i, j) ∧ 0 < j ⊦ ri0 = ri - rj ↔ ri = ri0 + rj

Rule argument

name: exrat-01 subst: [ri] → [ri]

Additional information

Used terms: ri