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Proof step 3 from proof elim-sub (previous step)

∃ i, j. ri = rational(i, j) ∧ 0 < j ⊦ ri0 = ri - rj ↔ ri = ri0 + rj

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 < j ⊦ ri0 = rational(i, j) - rj ↔ rational(i, j) = ri0 + rj

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)