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Proof step 5 from proof equality-def (previous step)

0 < j, 0 < j0 ⊦ rational(i, j) = rational(i0, j0) ↔ i * j0 = i0 * j

User applied rule case distinction

And obtained the following new goals

Proof step 6:
rational(i, j) = rational(i0, j0), 0 < j, 0 < j0 ⊦ i * j0 = i0 * j
Proof step 8:
i * j0 = i0 * j, 0 < j, 0 < j0 ⊦ rational(i, j) = rational(i0, j0)

Rule argument

pos: right 1

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