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Proof step 6 from proof equality-def (previous step)

rational(i, j) = rational(i0, j0), 0 < j, 0 < j0 ⊦ i * j0 = i0 * j

User applied rule insert lemma

And obtained the following new goals

Rule argument

name: equality-01 subst: [i, j, i0, j0] → [i, j, i0, j0]

Additional information

Used terms: i, j, i0, j0