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Proof step 2 from proof exrat-gcd1 (previous step)

⊦ ri = rational(0, 1), gcd(ri.num, ri.denom) = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ rj.num ≠ 0 → gcd(rj.num, rj.denom) = 1

Rule argument

name: gcd-num-one rotate: F subst: [rj] → [ri]

Additional information

Used simplifier rules: num-zero-denum-one: ⊦ rj.num = 0 → rj.denom = 1;% ⊦ gcd(i, 1) = 1; Used terms: ri