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Proof step 14 from proof int-mult (previous step)

j ≠ 0 ∧ 0 < 1 ⊦ i = 0, rational(j / gcd(j, 1) * i, rational(i, 1).denom * rational(j, 1).denom) = rational(i * j, 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
⊦ j = 0, i = 0, rational(j * i, rational(i, 1).denom * rational(j, 1).denom) = rational(i * j, 1)

Rule argument

Additional information

Used simplifier rules: ⊦ i / 1 = i;% ⊦ gcd(i, 1) = 1;