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Proof step 15 from proof int-mult (previous step)

⊦ j = 0, i = 0, rational(j * i, rational(i, 1).denom * rational(j, 1).denom) = rational(i * j, 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ i ≠ 0 ∧ j ≠ 0 → rational(i, j).denom = abs(j) / gcd(i, j)

Rule argument

name: denominator-pos rotate: F subst: [j, i] → [1, i]

Additional information

Used simplifier rules: denominator-pos: ⊦ i ≠ 0 ∧ j ≠ 0 → rational(i, j).denom = abs(j) / gcd(i, j);% ⊦ i * j = j * i;% ⊦ gcd(i, 1) = 1; Used terms: 1, i