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Proof step 14 from proof make (previous step)

i0 = 0, i0 ≤ 0 ⊦ rational(rational(i, i0).num, rational(i, i0).denom).num = rational(i, i0).num ∧ rational(rational(i, i0).num, rational(i, i0).denom).denom = rational(i, i0).denom, ¬ i ≤ 0 ∧ i0 ≠ 0, ¬ 0 ≤ i ∧ i0 ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information