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Proof step 15 from proof make (previous step)

⊦ rational(rational(i, 0).num, rational(i, 0).denom).num = rational(i, 0).num ∧ rational(rational(i, 0).num, rational(i, 0).denom).denom = rational(i, 0).denom

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: denominator-zero-den rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: numerator-zero: ⊦ rational(0, j).num = 0;%denominator-zero: ⊦ rational(0, j).denom = 1; Used terms: i