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Proof step 53 from proof make (previous step)

0 < i0 ⊦ i0 = 0, i = 0, rational(i / gcd(i, i0), i0 / gcd(i, i0)).num = i / gcd(i, i0) ∧ rational(i / gcd(i, i0), i0 / gcd(i, i0)).denom = i0 / gcd(i, i0), i / gcd(i, i0) ≠ 0 ∧ ¬ i0 / gcd(i, i0) ≤ 0

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 4

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