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Proof step 55 from proof make (previous step)

0 < i0 ⊦ ¬ i0 / gcd(i, i0) ≤ 0, i0 = 0, i = 0, rational(i / gcd(i, i0), i0 / gcd(i, i0)).num = i / gcd(i, i0) ∧ rational(i / gcd(i, i0), i0 / gcd(i, i0)).denom = i0 / gcd(i, i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
0 < i0, i0 / gcd(i, i0) ≤ 0, i0 / gcd(i, i0) < i0 ⊦ i0 = 0, i = 0, rational(i / gcd(i, i0), i0 / gcd(i, i0)).num = i / gcd(i, i0) ∧ rational(i / gcd(i, i0), i0 / gcd(i, i0)).denom = i0 / gcd(i, i0)

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)