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Proof step 2 from proof neg-intro (previous step)

⊦ j = 0, rational(i, ~ j) = rational(~ i, j)

User applied rule cut formula

And obtained the following new goals

Proof step 3:
i = ~ ~ i ⊦ j = 0, rational(i, ~ j) = rational(~ i, j)

Rule argument

fma: i = ~ ~ i

Additional information

Used simplifier rules: ⊦ ~ ~ i = i; Used formulas: i = ~ ~ i