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Proof step 3 from proof neg-intro (previous step)

i = ~ ~ i ⊦ j = 0, rational(i, ~ j) = rational(~ i, j)

User applied rule insert equation

And obtained the following new goals

Proof step 4:
⊦ j = 0, rational(~ ~ i, ~ j) = rational(~ i, j)

Rule argument

pos: left 1 flags: discard, [[2,2,1,1]]

Additional information