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Proof step 10 from proof negate-02 (previous step)

rational(0, 1) = ri1 + ri, rational(0, 1) = ri0 + ri1 ⊦ ri0 = ri

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: add-eq: ⊦ ri + rj = ri + rj0 ↔ rj = rj0;%add-asso: ⊦ (ri + rj) + rj0 = ri + rj + rj0;%add-comm: ⊦ ri + rj = rj + ri;