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Proof step 8 from proof negate-02 (previous step)

rational(0, 1) = ri0 + (rational(0, 1) - ri) ⊦ ri0 = ri

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
⊦ ri0 = ri - rj ↔ ri = ri0 + rj
Proof step 10:
rational(0, 1) = ri1 + ri, rational(0, 1) = ri0 + ri1 ⊦ ri0 = ri

Rule argument

name: elim-sub rotate: T subst: [ri, rj, ri0] → [rational(0, 1), ri, ri1]

Additional information

Used terms: rational(0, 1), ri, ri1