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Proof step 1 from proof zero-denom (conclusion)

⊦ rational(i, 0) = rational(i, 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ri = rj ↔ ri.num = rj.num ∧ ri.denom = rj.denom
Proof step 3:
⊦ rational(i, 0).num = rational(i, 1).num ∧ rational(i, 0).denom = rational(i, 1).denom

Rule argument

name: Equality rotate: F subst: [rj, ri] → [rational(i, 1), rational(i, 0)]

Additional information

Used terms: rational(i, 1), rational(i, 0)