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Proof step 3 from proof zero-denom (previous step)

⊦ rational(i, 0).num = rational(i, 1).num ∧ rational(i, 0).denom = rational(i, 1).denom

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i ≠ 0 → rational(i, 0).num = i
Proof step 5:
i ≠ 0 ⊦ i = rational(i, 1).num ∧ rational(i, 0).denom = rational(i, 1).denom

Rule argument

name: numerator-zero-den rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: numerator-zero: ⊦ rational(0, j).num = 0;%denominator-zero: ⊦ rational(0, j).denom = 1; Used terms: i