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Proof step 8 from proof downcase-A (previous step)

pos('A', sortedchars) ≤ pos('A', sortedchars) ∧ pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[pos('A', sortedchars) + (pos('a', sortedchars) - pos('A', sortedchars))] = 'a'

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[pos('A', sortedchars) + (pos('a', sortedchars) - pos('A', sortedchars))] = 'a'

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;