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Proof step 9 from proof downcase-A (previous step)

pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[pos('A', sortedchars) + (pos('a', sortedchars) - pos('A', sortedchars))] = 'a'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ pos('A', sortedchars) = 28
Proof step 11:
28 ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[28 + (pos('a', sortedchars) - 28)] = 'a'

Rule argument

spec: string-less inst: name: pos-A seq: ⊦ pos('A', sortedchars) = 28 subst: flags: rewrite

Additional information

Used terms: