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Proof step 12 from proof downcase-B (previous step)

pos('A', sortedchars) ≤ pos('B', sortedchars), pos('B', sortedchars) ≤ pos('Z', sortedchars), pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[pos('B', sortedchars) + (pos('a', sortedchars) - pos('A', sortedchars))] = 'b'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ pos('B', sortedchars) = 29
Proof step 14:
pos('A', sortedchars) ≤ 29, 29 ≤ pos('Z', sortedchars), pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[29 + (pos('a', sortedchars) - pos('A', sortedchars))] = 'b'

Rule argument

spec: string-less inst: name: pos-B seq: ⊦ pos('B', sortedchars) = 29 subst: flags: rewrite

Additional information

Used terms: