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Proof step 14 from proof downcase-B (previous step)

pos('A', sortedchars) ≤ 29, 29 ≤ pos('Z', sortedchars), pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[29 + (pos('a', sortedchars) - pos('A', sortedchars))] = 'b'

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
pos('A', sortedchars) ≤ 29, 29 ≤ pos('Z', sortedchars), pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[29 + (pos('a', sortedchars) - pos('A', sortedchars))] = 'b', pos('Z', sortedchars) = 0

Rule argument

Additional information

Used simplifier rules: 0 < n ⊦ (* n) ≤ m → m ≠ 0; (forward)