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Proof step 14 from proof pos-at (previous step)

s→l(str0)[m] ≠ char, m < # str0, ∀ n. n < # str0 → pos(s→l(str0)[n], str0) = n ⊦ pos(s→l(str0)[m], str0) + 1 = m + 1, char ' + str0 = "", str0 = "", char ∈ s→l(str0), dups(s→l(str0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
m < # str0, ∀ n. n < # str0 → pos(s→l(str0)[n], str0) = n ⊦ char ' + str0 = "", str0 = "", s→l(str0)[m] = char, pos(s→l(str0)[m], str0) = m, char ∈ s→l(str0), dups(s→l(str0))

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = m + n0 ↔ n = n0;