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Proof step 15 from proof pos-at (
previous step
)
m < # str0, ∀ n. n < # str0 → pos(s→l(str0)[n], str0) = n ⊦ char ' + str0 = "", str0 = "", s→l(str0)[m] = char, pos(s→l(str0)[m], str0) = m, char ∈ s→l(str0), dups(s→l(str0))
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: m
Additional information
Used terms: m