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Proof step 15 from proof sources-rec-01 (previous step)

⊦ sources(co ' + cl0, d) = (((∃ d0. d0 ∈ sources(cl0, d) ∧ cdom(co) ⇒ d0) ⊃ sources(cl0, d) ++ cdom(co); sources(cl0, d)))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 7:
∃ d0. d0 ∈ sources(cl0, d) ∧ cdom(co) ⇒ d0 ⊦ sources(co ' + cl0, d) = sources(cl0, d) ++ cdom(co)

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]