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Theorem sources-rec-01

⊦ cl ≠ [] → sources(cl, d) = (((∃ d0. d0 ∈ sources(cl .rest, d) ∧ cdom(cl .first) ⇒ d0) ⊃ sources(cl .rest, d) ++ cdom(cl .first); sources(cl .rest, d)))

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