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Proof step 2 from proof eqd-trans-lem (conclusion)

⊦ eqd(sys, d, sys0) ∧ eqd(sys0, d, sys1) → (¬ eqd(sys, d, sys1) ↔ false)

User applied rule insert lemma

And obtained the following new goals

Proof step 1:
⊦ eqd(sys, d, sys0) ∧ eqd(sys0, d, sys1) → eqd(sys, d, sys1)

Rule argument

[LEMMAARG : eqd-trans, [sys, d, sys0, sys1] → [sys, d, sys0, sys1]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sys, d, sys0, sys1)]]