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Proof step 2 from proof mk-exists (previous step)

∀ H0. # H0 < # ∅ → (true → (∃ rs, f. H0 = mk(rs, f))) ⊦ ∃ rs, f. ∅ = mk(rs, f)

User applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 1, [extquanttermlist: (∅, f)abort:F, discard:F, computed:F]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : emp, , , ⊦ mk(∅, f) = ∅])], [EXTRATERMS : (∅, f)]]