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Proof step 3 from proof mk-exists (previous step)

H = ∅, ∀ H0. # H0 < # H → (true → (∃ rs, f. H0 = mk(rs, f))) ⊦ ∃ rs, f. H = mk(rs, f)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
∀ H0. # H0 < # ∅ → (true → (∃ rs, f. H0 = mk(rs, f))) ⊦ ∃ rs, f. ∅ = mk(rs, f)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]