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Proof step 79 from proof alloc-p (previous step)

rely(me, O1(r ; me), H1 ++ r, O2, H2) ⊦ r = null, (!(me, O1, P) * P0)(H1) ↔ (!(me, O2, r =>_ * P) * P0)(H1 ++ r), r ∈ H1

User applied rule case distinction

And obtained the following new goals

Proof step 40:
(!(me, O1, P) * P0)(H1), rely(me, O1(r ; me), H1 ++ r, O2, H2) ⊦ (!(me, O2, r =>_ * P) * P0)(H1 ++ r), r = null, r ∈ H1

Rule argument

[CASEDARG : pos: right 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]