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Proof step 80 from proof alloc-p (conclusion)

⊦ r ≠ null ∧ ¬ r ∈ H1 ∧ rely(me, O1(r ; me), H1 ++ r, O2, H2) → ((!(me, O1, P) * P0)(H1) ↔ (!(me, O2, r =>_ * P) * P0)(H1 ++ r))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 79:
rely(me, O1(r ; me), H1 ++ r, O2, H2) ⊦ r = null, (!(me, O1, P) * P0)(H1) ↔ (!(me, O2, r =>_ * P) * P0)(H1 ++ r), r ∈ H1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]