⊦ (P0 * P1)(H) ↔ (∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P0(H0) ∧ P1(H1))
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (H, P, !(me, O, _∃ oP * P0))]]