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Proof step 32 from proof ex-shift-o-p (conclusion)

⊦ (!(me, O, _∃ oP * P0) * P)(H) ↔ (∃ o. (!(me, O, oP(o) * P0) * P)(H))

User applied rule case distinction

And obtained the following new goals

Proof step 17:
(!(me, O, _∃ oP * P0) * P)(H) ⊦ ∃ o. (!(me, O, oP(o) * P0) * P)(H)

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]