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Proof step 1 from proof floor-int (conclusion)
(back to tree)
System applied rule normalize
And obtained the following new goals
Rule argument
Additional information
User applied rule apply lemma
And obtained the following new goals
Rule argument
spec: <toplevel>, name:floor-le, seq: ⊦ ⌊r⌋ .r ≤ r, subst:[r] → [i.r]
Additional information
Used terms: i.r
| ⌊i.r⌋ ≠ i, ⌊i.r⌋ .r ≤ i.r ⊦ |
User applied rule apply lemma
And obtained the following new goals
Rule argument
spec: <toplevel>, name:floor-gr-subone, seq: ⊦ r < ⌊r⌋ .r + 1.r,
subst:[r] → [i.r]
Additional information
Used terms: i.r
| ⌊i.r⌋ ≠ i, i.r < ⌊i.r⌋ .r + 1.r, ⌊i.r⌋ .r ≤ i.r ⊦ |
User applied rule apply rewrite lemma
And obtained the following new goals
Rule argument
spec: real-basic, name: eqint-add, seq: ⊦ (* i).r + (* j).r = (i + j).r,
subst:[i, j] → [⌊i.r⌋ , 1], <all paths>
Additional information
Used terms: ⌊i.r⌋ , 1
| ⊦ (* i).r + (* j).r = (i + j).r |
A spec-lemma
| ⌊i.r⌋ ≠ i, i.r < (⌊i.r⌋ + 1).r, ⌊i.r⌋ .r ≤ i.r ⊦ |
User applied rule apply rewrite lemma
And obtained the following new goals
Rule argument
spec: real-basic, name: ls-num, seq: ⊦ i.r < j.r ↔ i < j,
subst:[i, j] → [i, ⌊i.r⌋ + 1], <all paths>
Additional information
Used terms: i, ⌊i.r⌋ + 1
| ⌊i.r⌋ ≠ i, i < ⌊i.r⌋ + 1, ⌊i.r⌋ .r ≤ i.r ⊦ |
User applied rule apply rewrite lemma
And obtained the following new goals
Rule argument
spec: real-abs, name: le-num, seq: ⊦ i.r ≤ j.r ↔ i ≤ j, subst:[i, j] → [⌊i.r⌋ , i],
<all paths>
Additional information
Used simplifier rules:
⊦ i ≠ j → (i ≤ j ↔ i < j); (s)
⊦ i < j + 1 ↔ i ≤ j; (s)
⊦ i < j → (j ≤ i ↔ false); (as)
add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2
add-c: ⊦ i + j = j + i; from specification int-basic2
Used terms: ⌊i.r⌋ , i
Proof Tree for floor-int
(View conclusion)
The following image shows the proof tree of sequent calculus. The
proved goal is at the bottom. You can click on the nodes to view
additional rules. See here for details on colors in a proof
tree.