[Imprint][Data Privacy Statement][E-Mail]

Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Theorem base for Specification nat-pot

This is a listing of all goals defined over the current specification. Axioms are marked yellow, proved theorems green and unproved theorems blue. Click on individual names to get more information on the proof.

Name: Sequent: Type:
inj-02 ⊦ 2^ n = 2 * 2^ m ↔ n = m + 1 A User Theorem
power-of-2 ⊦ 2 ^ m ≠ 1 → 2 * 2 ^ m / 2 = 2 ^ m A User Theorem
mult ⊦ (m * m0) ^ n = m ^ n * m0 ^ n A User Theorem
Pot2-zero ⊦ 2^ 0 = 1 An Axiom
laddm ≠ 0 ⊦ ¬ log2(m + n) < log2 m A User Theorem
pot-mon1 < m ⊦ m ^ n < m ^ n0 ↔ n < n0 A User Theorem
pot-01n ≠ 0 ⊦ 2 * 2^ n.-1 = 2^ n A User Theorem
lzer ⊦ log2(m + 1) = 0 ↔ m = 0 A User Theorem
Pot-succ ⊦ n ^ m.+1 = n ^ m * n An Axiom
zero ⊦ 2^ n ≠ 0 A User Theorem
rec ⊦ 2^(n + 1) = 2^ n + 2^ n A User Theorem
potmonleq ⊦ 2^ m ≤ 2^ n ↔ m ≤ n A User Theorem
pot2-def ⊦ 2^ m = 2 ^ m A User Theorem
log2-elimm ≠ 0 ⊦ n = log2 m ↔ (∃ m0. m = 2^ n + m0 ∧ m0 < 2^ n) A User Theorem
potexn ≠ 0 ⊦ ∃ m. 2^ m ≤ n ∧ n < 2^(m + 1) A User Theorem
Pot-zero ⊦ n ^ 0 = 1 An Axiom
rec-01 ⊦ n ^ (m + 1) = n ^ m * n A User Theorem
div-eq-zerom0 ≠ 0 ⊦ n0 / m0 = 0 ↔ n0 < m0 A User Theorem
Logdef ⊦ m ^ n0 ≤ n ∧ n < m ^ n0.+1 → log(m, n) = n0 An Axiom
lemma-ax2 ⊦ 2^(n + 1) = 2 * 2^ n A User Theorem
add ⊦ m ^ (n + n0) = m ^ n * m ^ n0 A User Theorem
Pot2-succ ⊦ 2^ n.+1 = 2 * 2^ n An Axiom
two-pot-zero ⊦ 2 ^ n ≠ 0 A User Theorem
Log2def ⊦ 2^ m ≤ n ∧ n < 2^ m.+1 → log2 n = m An Axiom
lsucc-01 ⊦ n ≠ 0 → log2(2 * n + 1) = log2 n + 1 A User Theorem
ltwo-05 ⊦ n < 2 * 2^ log2 n A User Theorem
ltwo-04 ⊦ log2 2 = 1 A User Theorem
ltwo-03 ⊦ n ≠ 0 → log2(2 * n) = log2 n + 1 A User Theorem
pot-zero-01 ⊦ n ≠ 0 → 0 ^ n = 0 A User Theorem
pot-two ⊦ m ^ 2 = m * m A User Theorem
lone ⊦ log2 1 = 0 A User Theorem
zero-01 ⊦ 0 ^ n = 0 ↔ n ≠ 0 A User Theorem
two ⊦ m ^ (2 * n) = m ^ n * m ^ n A User Theorem
pot2-add ⊦ 2^(m + n) = 2^ m * 2^ n A User Theorem
power-of-2-01 ⊦ 2 ^ m ≠ 1 → 4 * 2 ^ m / 2 * n = 2 * n * 2 ^ m A User Theorem
ladd-01n ≠ 0 ⊦ m = n + n0 → ¬ log2 m < log2 n A User Theorem
succ-02 ⊦ 2 * 2^ m = 2^(m + 1) A User Theorem
succ-03 ⊦ 2^ m = 2 * n + 1 ↔ m = 0 ∧ n = 0 A User Theorem
lpot ⊦ log2 2^ n = n A User Theorem
pot-zero ⊦ m ≠ 0 → m ^ n ≠ 0 A User Theorem
2-pot-mod ⊦ m ≠ 0 → 2 ^ m % 2 = 0 A User Theorem
2-pot-mod-01 ⊦ 2 ^ m ≠ 1 → 2 ^ m % 2 = 0 A User Theorem
inj ⊦ 2^ n = 2^ m ↔ n = m A User Theorem
potmon ⊦ 2^ m < 2^ n ↔ m < n A User Theorem
one ⊦ 2^ m = 1 ↔ m = 0 A User Theorem
lls-01 ⊦ n < 2^(log2 n + 1) A User Theorem
lls-02n ≠ 0 ⊦ log2 m < log2 n → m < n A User Theorem
one-01 ⊦ 2^ 1 = 2 A User Theorem
one-01-01 ⊦ m ^ 1 = m A User Theorem
one-02 ⊦ 0 ^ 1 = 0 A User Theorem
lls ⊦ n ≠ 0 → ¬ n < 2^ log2 n A User Theorem