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Proof step 1 from proof square-le (conclusion) (back to tree)

⊦ r * r ≤ r0 * r0 ↔ abs(r) ≤ abs(r0)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information

Proof step 2 from proof square-le (previous step) (back to tree)

¬(r * r ≤ r0 * r0 ↔ abs(r) ≤ abs(r0)) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: abs-ite: ⊦ abs(r) = (r < 0.r ⊃ ~ r;r);

Proof step 3 from proof square-le (previous step) (back to tree)

¬(r * r ≤ r0 * r0 ↔ (r < 0.r ⊃ ~ r;r) ≤ (r0 < 0.r ⊃ ~ r0;r0)) ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information

Proof step 4 from proof square-le (previous step) (back to tree)

r * r ≤ r0 * r0, ¬ (r < 0.r ⊃ ~ r;r) ≤ (r0 < 0.r ⊃ ~ r0;r0) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss)

Proof step 5 from proof square-le (previous step) (back to tree)

(r0 < 0.r ⊃ ~ r0;r0) < (r < 0.r ⊃ ~ r;r), r * r ≤ r0 * r0 ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information

Proof step 6 from proof square-le (previous step) (back to tree)

r * r ≤ r0 * r0, r0 < 0.r, ~ r0 < (r < 0.r ⊃ ~ r;r) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: trans: ⊦ r < r0 ∧ r0 < r1 → r < r1; (forward) from specification real-basic add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ r < r + r0 ↔ 0.r < r0; (s) ⊦ ~ r < r0 ↔ 0.r < r0 + r; (s)

Proof step 7 from proof square-le (previous step) (back to tree)

0.r < (r < 0.r ⊃ ~ r;r) + r0, 0.r < (r < 0.r ⊃ ~ r;r), r * r ≤ r0 * r0, r0 < 0.r, r0 < (r < 0.r ⊃ ~ r;r) ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information

Proof step 8 from proof square-le (previous step) (back to tree)

0.r < (r < 0.r ⊃ ~ r;r), 0.r < ~ r + r0, r * r ≤ r0 * r0, r < 0.r, r0 < (r < 0.r ⊃ ~ r;r), r0 < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: trans: ⊦ r < r0 ∧ r0 < r1 → r < r1; (forward) from specification real-basic ⊦ 0.r < ~ r ↔ r < 0.r; (s) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ 0.r < r + ~ r0 ↔ r0 < r; (s) ⊦ r < 0.r ∧ r0 < 0.r → r + r0 < 0.r; (s) ⊦ r0 < ~ r ↔ r0 + r < 0.r; (s)

Proof step 9 from proof square-le (previous step) (back to tree)

r * r ≤ r0 * r0, r < r0, r < 0.r, r0 < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: transrew, seq: ⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1, subst:[r, r0, r1] → [r * r0, r * r, r0 * r0], <all paths>

Additional information

Used simplifier rules: le-neg: ⊦ r < 0.r → (r * r0 ≤ r * r1 ↔ r1 ≤ r0); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r < r0 → (r0 ≤ r ↔ false); (as) ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss) ⊦ r < r0 → ¬ r0 < r; (s) Used terms: r * r0, r * r, r0 * r0

Proof step 10 from proof square-le (previous step) (back to tree)

⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1

A spec-lemma

Proof step 11 from proof square-le (previous step) (back to tree)

0.r < (r < 0.r ⊃ ~ r;r), 0.r < r + r0, r * r ≤ r0 * r0, r0 < (r < 0.r ⊃ ~ r;r), r0 < 0.r, ¬ r < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ 0.r < r → r0 < r0 + r; (s) trans: ⊦ r < r0 ∧ r0 < r1 → r < r1; (forward) from specification real-basic ⊦ r < r0 → ¬ r0 < r; (s)

Proof step 12 from proof square-le (previous step) (back to tree)

0.r < r, 0.r < r + r0, r * r ≤ r0 * r0, r0 < r, r0 < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: transrew, seq: ⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1, subst:[r, r0, r1] → [r * ~ r0, r * r, r0 * r0], <all paths>

Additional information

Used terms: r * ~ r0, r * r, r0 * r0

Proof step 13 from proof square-le (previous step) (back to tree)

⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1

A spec-lemma

Proof step 14 from proof square-le (previous step) (back to tree)

0.r < r + r0, 0.r < r, r * r ≤ r0 * r0, r0 < 0.r, r0 < r ⊦ ¬ r * ~ r0 ≤ r0 * r0 ∧ r * ~ r0 ≤ r * r

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Proof step 15 from proof square-le (previous step) (back to tree)

0.r < r, 0.r < r + r0, r * ~ r0 ≤ r0 * r0, r * r ≤ r0 * r0, r0 < r, r0 < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r0, r], <all paths>

Additional information

Used simplifier rules: mult-com: ⊦ r * r0 = r0 * r; Used terms: r0, r

Proof step 16 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 17 from proof square-le (previous step) (back to tree)

0.r < r + r0, 0.r < r, r * r ≤ r0 * r0, r0 < 0.r, r0 < r, ~(r0 * r) ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: mult-com, seq: ⊦ r * r0 = r0 * r, subst:[r, r0] → [r0, r], <all paths>

Additional information

Used terms: r0, r

Proof step 18 from proof square-le (previous step) (back to tree)

⊦ r * r0 = r0 * r

Lemma mult-com

Proof step 19 from proof square-le (previous step) (back to tree)

0.r < r, 0.r < r + r0, r * r ≤ r0 * r0, r0 < r, r0 < 0.r, ~(r * r0) ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r, r0], <rotated> <all paths>

Additional information

Used terms: r, r0

Proof step 20 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 21 from proof square-le (previous step) (back to tree)

0.r < r + r0, 0.r < r, r * r ≤ r0 * r0, r0 < 0.r, r0 < r, ~ r * r0 ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: le-neg-01, seq: ⊦ r < 0.r → (r0 * r ≤ r1 * r ↔ r1 ≤ r0), subst:[r0, r, r1] → [~ r, r0, r0], <all paths>

Additional information

Used simplifier rules: ⊦ r ≤ ~ r0 ↔ r + r0 ≤ 0.r; (s) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic ⊦ r < r0 → (r0 ≤ r ↔ false); (as) Used terms: ~ r, r0, r0

Proof step 22 from proof square-le (previous step) (back to tree)

⊦ r < 0.r → (r0 * r ≤ r1 * r ↔ r1 ≤ r0)

Lemma le-neg-01

Proof step 23 from proof square-le (previous step) (back to tree)

0.r < r, 0.r < r + r0, r * r ≤ r0 * r0, r0 < r, r0 < 0.r, ¬ r * ~ r0 ≤ r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: ple-pos, seq:0.r < r, 0.r < r0, r ≤ r1, r0 ≤ r2 ⊦ r * r0 ≤ r1 * r2, subst:[r, r0, r1, r2] → [r, ~ r0, r, r], <all paths>

Additional information

Used simplifier rules: minus-left: ⊦ ~ r * r0 = ~(r * r0); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ 0.r < ~ r ↔ r < 0.r; (s) ⊦ r ≤ r; (s) ⊦ ~ r ≤ r0 ↔ 0.r ≤ r + r0; (s) ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic ⊦ r < r0 → ¬ r0 < r; (s) Used terms: r, ~ r0, r, r

Proof step 24 from proof square-le (previous step) (back to tree)

0.r < r, 0.r < r0, r ≤ r1, r0 ≤ r2 ⊦ r * r0 ≤ r1 * r2

Lemma ple-pos

Proof step 25 from proof square-le (previous step) (back to tree)

r * r ≤ r0 * r0, r0 < (r < 0.r ⊃ ~ r;r), ¬ r0 < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ r ≤ r0 ∧ r0 < r1 → r < r1; (forward) from specification real-abs ⊦ r < r0 ↔ ¬ r0 ≤ r; (ss)

Proof step 26 from proof square-le (previous step) (back to tree)

0.r ≤ r0, 0.r < (r < 0.r ⊃ ~ r;r), r * r ≤ r0 * r0, r0 < (r < 0.r ⊃ ~ r;r) ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 4

Additional information

Proof step 27 from proof square-le (previous step) (back to tree)

0.r < (r < 0.r ⊃ ~ r;r), 0.r ≤ r0, r * r ≤ r0 * r0, r < 0.r, r0 < ~ r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ r + r0 < r0 ↔ r < 0.r; (s) ⊦ r < 0.r ∧ 0.r ≤ r0 → r < r0; (s) forward-lsle: ⊦ r < r0 ∧ r0 ≤ r1 → r < r1; (forward) from specification real-abs ⊦ 0.r < ~ r ↔ r < 0.r; (s) ⊦ r0 < ~ r ↔ r0 + r < 0.r; (s)

Proof step 28 from proof square-le (previous step) (back to tree)

0.r ≤ r0, r * r ≤ r0 * r0, r < 0.r, r0 + r < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: antr, seq: ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0), subst:[r0, r] → [0.r, r0], <all paths>

Additional information

Used simplifier rules: mult-zero: ⊦ 0.r * r = 0.r; zero-le-01: ⊦ r < 0.r → (r * r0 ≤ 0.r ↔ 0.r ≤ r0); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r ≤ r; (s) ⊦ r < r0 → (r0 ≤ r ↔ false); (as) Used terms: 0.r, r0

Proof step 29 from proof square-le (previous step) (back to tree)

⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0)

A spec-lemma

Proof step 30 from proof square-le (previous step) (back to tree)

0.r ≤ r0, r < 0.r, r * r ≤ r0 * r0, r0 + r < 0.r, ¬ r0 ≤ 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r ≠ r0 → (r ≤ r0 ↔ r < r0); (s) ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0); (s)

Proof step 31 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, r * r ≤ r0 * r0, r < 0.r, r0 + r < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: transrew, seq: ⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1, subst:[r, r0, r1] → [r0 * ~ r, r * r, r0 * r0], <all paths>

Additional information

Used terms: r0 * ~ r, r * r, r0 * r0

Proof step 32 from proof square-le (previous step) (back to tree)

⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1

A spec-lemma

Proof step 33 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, r < 0.r, r * r ≤ r0 * r0, r0 + r < 0.r ⊦ ¬ r0 * ~ r ≤ r0 * r0 ∧ r0 * ~ r ≤ r * r

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Proof step 34 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, r * r ≤ r0 * r0, r < 0.r, r0 * ~ r ≤ r0 * r0, r0 + r < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: le-pos, seq: ⊦ 0.r < r → (r * r0 ≤ r * r1 ↔ r0 ≤ r1), subst:[r, r0, r1] → [r0, ~ r, r0], <all paths>

Additional information

Used simplifier rules: ⊦ ~ r ≤ r0 ↔ 0.r ≤ r + r0; (s) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic ⊦ r < r0 → (r0 ≤ r ↔ false); (as) Used terms: r0, ~ r, r0

Proof step 35 from proof square-le (previous step) (back to tree)

⊦ 0.r < r → (r * r0 ≤ r * r1 ↔ r0 ≤ r1)

Lemma le-pos

Proof step 36 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, r * r ≤ r0 * r0, r < 0.r, r0 + r < 0.r, ¬ r0 * ~ r ≤ r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r, r0], <all paths>

Additional information

Used simplifier rules: mult-com: ⊦ r * r0 = r0 * r; Used terms: r, r0

Proof step 37 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 38 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, r < 0.r, r * r ≤ r0 * r0, r0 + r < 0.r, ¬ ~(r * r0) ≤ r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: mult-com, seq: ⊦ r * r0 = r0 * r, subst:[r, r0] → [r, r0], <all paths>

Additional information

Used terms: r, r0

Proof step 39 from proof square-le (previous step) (back to tree)

⊦ r * r0 = r0 * r

Lemma mult-com

Proof step 40 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, r * r ≤ r0 * r0, r < 0.r, r0 + r < 0.r, ¬ ~(r0 * r) ≤ r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r0, r], <rotated> <all paths>

Additional information

Used terms: r0, r

Proof step 41 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 42 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, r < 0.r, r * r ≤ r0 * r0, r0 + r < 0.r, ¬ ~ r0 * r ≤ r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: le-neg-01, seq: ⊦ r < 0.r → (r0 * r ≤ r1 * r ↔ r1 ≤ r0), subst:[r0, r, r1] → [~ r0, r, r], <all paths>

Additional information

Used simplifier rules: ⊦ r ≤ ~ r0 ↔ r + r0 ≤ 0.r; (s) ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic ⊦ r < r0 → ¬ r0 < r; (s) Used terms: ~ r0, r, r

Proof step 43 from proof square-le (previous step) (back to tree)

⊦ r < 0.r → (r0 * r ≤ r1 * r ↔ r1 ≤ r0)

Lemma le-neg-01

Proof step 44 from proof square-le (previous step) (back to tree)

0.r < (r < 0.r ⊃ ~ r;r), 0.r ≤ r0, r * r ≤ r0 * r0, r0 < r, ¬ r < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ r < r0 ∧ 0.r ≤ r → 0.r < r0; (forward) from specification real-abs ⊦ r < r0 → ¬ r0 < r; (s)

Proof step 45 from proof square-le (previous step) (back to tree)

0.r ≤ r0, 0.r < r, r * r ≤ r0 * r0, r0 < r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: transrew, seq: ⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1, subst:[r, r0, r1] → [r * r0, r * r, r0 * r0], <all paths>

Additional information

Used terms: r * r0, r * r, r0 * r0

Proof step 46 from proof square-le (previous step) (back to tree)

⊦ ¬ r ≤ r1 ∧ r ≤ r0 → ¬ r0 ≤ r1

A spec-lemma

Proof step 47 from proof square-le (previous step) (back to tree)

0.r < r, 0.r ≤ r0, r * r ≤ r0 * r0, r0 < r ⊦ ¬ r * r0 ≤ r0 * r0 ∧ r * r0 ≤ r * r

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Used simplifier rules: le-pos: ⊦ 0.r < r → (r * r0 ≤ r * r1 ↔ r0 ≤ r1); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss) ⊦ r < r0 → ¬ r0 < r; (s)

Proof step 48 from proof square-le (previous step) (back to tree)

0.r ≤ r0, 0.r < r, r * r0 ≤ r0 * r0, r * r ≤ r0 * r0, r0 < r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: le-pos-01, seq: ⊦ 0.r < r → (r0 * r ≤ r1 * r ↔ r0 ≤ r1), subst:[r0, r, r1] → [r, r0, r0], <all paths>

Additional information

Used simplifier rules: mult-zero: ⊦ 0.r * r = 0.r; zero-le: ⊦ 0.r < r → (r * r0 ≤ 0.r ↔ r0 ≤ 0.r); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r < r0 → (r0 ≤ r ↔ false); (as) ⊦ r < r0 ↔ ¬ r0 ≤ r; (ss) ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0); (s) lf-03: ⊦ r < r0 ∧ r = r1 → r1 < r0; (forward) from specification real-basic ⊦ r ≤ r; (s) Used terms: r, r0, r0

Proof step 49 from proof square-le (previous step) (back to tree)

⊦ 0.r < r → (r0 * r ≤ r1 * r ↔ r0 ≤ r1)

Lemma le-pos-01

Proof step 50 from proof square-le (previous step) (back to tree)

(r < 0.r ⊃ ~ r;r) ≤ (r0 < 0.r ⊃ ~ r0;r0), ¬ r * r ≤ r0 * r0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss)

Proof step 51 from proof square-le (previous step) (back to tree)

(r < 0.r ⊃ ~ r;r) ≤ (r0 < 0.r ⊃ ~ r0;r0), r0 * r0 < r * r ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information

Proof step 52 from proof square-le (previous step) (back to tree)

r < 0.r, r0 * r0 < r * r, ~ r ≤ (r0 < 0.r ⊃ ~ r0;r0) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r < 0.r ∧ 0.r ≤ r0 → r < r0; (s) forward-lsle: ⊦ r < r0 ∧ r0 ≤ r1 → r < r1; (forward) from specification real-abs ⊦ ~ r ≤ r0 ↔ 0.r ≤ r + r0; (s)

Proof step 53 from proof square-le (previous step) (back to tree)

0.r ≤ r + (r0 < 0.r ⊃ ~ r0;r0), r < 0.r, r0 * r0 < r * r ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information

Proof step 54 from proof square-le (previous step) (back to tree)

0.r ≤ r + ~ r0, r < 0.r, r0 * r0 < r * r, r0 < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ r ≤ r0 ∧ r0 < r1 → r < r1; (forward) from specification real-abs add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ r + 0.r = r; (s) ⊦ r ≤ r0 + ~ r1 ↔ r + r1 ≤ r0; (s)

Proof step 55 from proof square-le (previous step) (back to tree)

r < 0.r, r0 * r0 < r * r, r0 ≤ r, r0 < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-basic, name: trans-lem, seq:¬ r < r1, r < r0 ⊦ ¬ r0 < r1, subst:[r, r0, r1] → [r * r0, r0 * r0, r * r], <all paths>

Additional information

Used simplifier rules: ls-neg: ⊦ r < 0.r → (r * r0 < r * r2 ↔ r2 < r0); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r < r0 ↔ ¬ r0 ≤ r; (ss) ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0); (s) lf-03: ⊦ r < r0 ∧ r = r1 → r1 < r0; (forward) from specification real-basic ⊦ r ≤ r0 → ¬ r0 < r; (s) Used terms: r * r0, r0 * r0, r * r

Proof step 56 from proof square-le (previous step) (back to tree)

¬ r < r1, r < r0 ⊦ ¬ r0 < r1

A spec-lemma

Proof step 57 from proof square-le (previous step) (back to tree)

0.r ≤ r + r0, r < 0.r, r0 * r0 < r * r, ¬ r0 < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r < 0.r ∧ 0.r ≤ r0 → r < r0; (s) forward-lsle: ⊦ r < r0 ∧ r0 ≤ r1 → r < r1; (forward) from specification real-abs ⊦ r < r0 ↔ ¬ r0 ≤ r; (ss)

Proof step 58 from proof square-le (previous step) (back to tree)

0.r ≤ r0, 0.r ≤ r + r0, r < 0.r, r0 * r0 < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: antr, seq: ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0), subst:[r0, r] → [0.r, r0], <all paths>

Additional information

Used simplifier rules: ⊦ r ≤ r; (s) ⊦ r + 0.r = r; (s) add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic add-comm: ⊦ r + r0 = r0 + r; from specification real-basic ⊦ r < r0 → (r0 ≤ r ↔ false); (as) Used terms: 0.r, r0

Proof step 59 from proof square-le (previous step) (back to tree)

⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0)

A spec-lemma

Proof step 60 from proof square-le (previous step) (back to tree)

0.r ≤ r + r0, 0.r ≤ r0, r < 0.r, r0 * r0 < r * r, ¬ r0 ≤ 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r ≠ r0 → (r ≤ r0 ↔ r < r0); (s) ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0); (s)

Proof step 61 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≤ r + r0, 0.r < r0, r < 0.r, r0 * r0 < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: antr, seq: ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0), subst:[r0, r] → [0.r, r + r0], <all paths>

Additional information

Used terms: 0.r, r + r0

Proof step 62 from proof square-le (previous step) (back to tree)

⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0)

A spec-lemma

Proof step 63 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r < r0, 0.r ≤ r + r0, r < 0.r, r0 * r0 < r * r, ¬ r + r0 ≤ 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r ≠ r0 → (r ≤ r0 ↔ r < r0); (s) ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0); (s)

Proof step 64 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r0, 0.r < r + r0, r < 0.r, r0 * r0 < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-basic, name: trans-lem, seq:¬ r < r1, r < r0 ⊦ ¬ r0 < r1, subst:[r, r0, r1] → [r0 * ~ r, r0 * r0, r * r], <all paths>

Additional information

Used terms: r0 * ~ r, r0 * r0, r * r

Proof step 65 from proof square-le (previous step) (back to tree)

¬ r < r1, r < r0 ⊦ ¬ r0 < r1

A spec-lemma

Proof step 66 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r + r0, 0.r < r0, r < 0.r, r0 * r0 < r * r ⊦ ¬ r0 * ~ r < r * r ∧ r0 * ~ r < r0 * r0

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Proof step 67 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r0, 0.r < r + r0, r < 0.r, r0 * ~ r < r * r, r0 * r0 < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r, r0], <all paths>

Additional information

Used simplifier rules: mult-com: ⊦ r * r0 = r0 * r; Used terms: r, r0

Proof step 68 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 69 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r + r0, 0.r < r0, r < 0.r, r0 * r0 < r * r, ~(r * r0) < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: mult-com, seq: ⊦ r * r0 = r0 * r, subst:[r, r0] → [r, r0], <all paths>

Additional information

Used terms: r, r0

Proof step 70 from proof square-le (previous step) (back to tree)

⊦ r * r0 = r0 * r

Lemma mult-com

Proof step 71 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r0, 0.r < r + r0, r < 0.r, r0 * r0 < r * r, ~(r0 * r) < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r0, r], <rotated> <all paths>

Additional information

Used terms: r0, r

Proof step 72 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 73 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r + r0, 0.r < r0, r < 0.r, r0 * r0 < r * r, ~ r0 * r < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: mult-com, seq: ⊦ r * r0 = r0 * r, subst:[r, r0] → [~ r0, r], <all paths>

Additional information

Used terms: ~ r0, r

Proof step 74 from proof square-le (previous step) (back to tree)

⊦ r * r0 = r0 * r

Lemma mult-com

Proof step 75 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r0, 0.r < r + r0, r * ~ r0 < r * r, r < 0.r, r0 * r0 < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: ls-neg, seq: ⊦ r < 0.r → (r * r0 < r * r2 ↔ r2 < r0), subst:[r, r0, r2] → [r, ~ r0, r], <all paths>

Additional information

Used simplifier rules: ⊦ r0 < ~ r ↔ r0 + r < 0.r; (s) ⊦ r < r0 → ¬ r0 < r; (s) Used terms: r, ~ r0, r

Proof step 76 from proof square-le (previous step) (back to tree)

⊦ r < 0.r → (r * r0 < r * r2 ↔ r2 < r0)

Lemma ls-neg

Proof step 77 from proof square-le (previous step) (back to tree)

0.r ≠ r0, 0.r ≠ r + r0, 0.r < r0, 0.r < r + r0, r < 0.r, r0 * r0 < r * r, ¬ r0 * ~ r < r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: ls-pos, seq: ⊦ 0.r < r → (r * r0 < r * r2 ↔ r0 < r2), subst:[r, r0, r2] → [r0, ~ r, r0], <all paths>

Additional information

Used simplifier rules: ⊦ ~ r < r0 ↔ 0.r < r0 + r; (s) ⊦ r < r0 ↔ ¬ r0 ≤ r; (ss) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic ⊦ r < r0 → (r0 ≤ r ↔ false); (as) Used terms: r0, ~ r, r0

Proof step 78 from proof square-le (previous step) (back to tree)

⊦ 0.r < r → (r * r0 < r * r2 ↔ r0 < r2)

Lemma ls-pos

Proof step 79 from proof square-le (previous step) (back to tree)

r + r0 = 0.r, 0.r ≠ r0, 0.r < r0, r < 0.r, r + r0 ≤ 0.r, r0 * r0 < r * r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r ≤ r; (s) ⊦ r < 0.r ∧ 0.r ≤ r0 → r < r0; (s) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ r + r0 < r0 ↔ r < 0.r; (s) forward-lsle: ⊦ r < r0 ∧ r0 ≤ r1 → r < r1; (forward) from specification real-abs forward-le-05: ⊦ r < r0 ∧ 0.r ≤ r → 0.r < r0; (forward) from specification real-abs lf-03: ⊦ r < r0 ∧ r = r1 → r1 < r0; (forward) from specification real-basic

Proof step 80 from proof square-le (previous step) (back to tree)

r + r0 = 0.r, 0.r ≠ r0, 0.r < r0, r < 0.r, r0 * r0 < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-basic, name: negeq, seq: ⊦ ~ r = r0 ↔ r + r0 = 0.r, subst:[r, r0] → [r, r0], <rotated> <all paths>

Additional information

Used simplifier rules: minus-left: ⊦ ~ r * r0 = ~(r * r0); ls-neg: ⊦ r < 0.r → (r * r0 < r * r2 ↔ r2 < r0); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ ~ r = 0.r ↔ r = 0.r; (s) ⊦ ~ ~ r = r; (s) ⊦ ¬ r < r; (s) Used terms: r, r0

Proof step 81 from proof square-le (previous step) (back to tree)

⊦ ~ r = r0 ↔ r + r0 = 0.r

A spec-lemma

Proof step 82 from proof square-le (previous step) (back to tree)

r ≤ (r0 < 0.r ⊃ ~ r0;r0), r0 * r0 < r * r, ¬ r < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-lele: ⊦ r ≤ r0 ∧ r0 ≤ r1 → r ≤ r1; (forward) from specification real-abs ⊦ r < r0 ↔ ¬ r0 ≤ r; (ss)

Proof step 83 from proof square-le (previous step) (back to tree)

0.r ≤ r, 0.r ≤ (r0 < 0.r ⊃ ~ r0;r0), r ≤ (r0 < 0.r ⊃ ~ r0;r0), r0 * r0 < r * r ⊦

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 3

Additional information

Proof step 84 from proof square-le (previous step) (back to tree)

0.r ≤ (r0 < 0.r ⊃ ~ r0;r0), 0.r ≤ r, r ≤ ~ r0, r0 * r0 < r * r, r0 < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ r < 0.r ∧ 0.r ≤ r0 → r < r0; (s) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ r + r0 ≤ r ↔ r0 ≤ 0.r; (s) ⊦ r < 0.r ∧ 0.r ≤ r0 → r ≤ r0; (s) forward-lsle: ⊦ r < r0 ∧ r0 ≤ r1 → r < r1; (forward) from specification real-abs forward-lele: ⊦ r ≤ r0 ∧ r0 ≤ r1 → r ≤ r1; (forward) from specification real-abs ⊦ r + 0.r = r; (s) ⊦ r ≤ ~ r0 ↔ r + r0 ≤ 0.r; (s)

Proof step 85 from proof square-le (previous step) (back to tree)

0.r ≤ r, r + r0 ≤ 0.r, r0 * r0 < r * r, r0 < 0.r, r0 ≤ 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: antr, seq: ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0), subst:[r0, r] → [0.r, r], <all paths>

Additional information

Used simplifier rules: mult-zero: ⊦ 0.r * r = 0.r; zero-ls-01: ⊦ r < 0.r → (r * r0 < 0.r ↔ 0.r < r0); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r < r0 → ¬ r0 < r; (s) Used terms: 0.r, r

Proof step 86 from proof square-le (previous step) (back to tree)

⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0)

A spec-lemma

Proof step 87 from proof square-le (previous step) (back to tree)

0.r ≤ r, r + r0 ≤ 0.r, r0 ≤ 0.r, r0 < 0.r, r0 * r0 < r * r, ¬ r ≤ 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-comm: ⊦ r + r0 = r0 + r; from specification real-basic add-assoc: ⊦ (r + r0) + r1 = r + r0 + r1; from specification real-basic ⊦ r + r0 < r0 ↔ r < 0.r; (s) forward-lels: ⊦ r ≤ r0 ∧ r0 < r1 → r < r1; (forward) from specification real-abs ⊦ r ≠ r0 → (r ≤ r0 ↔ r < r0); (s) ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0); (s)

Proof step 88 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 ≤ 0.r, r0 * r0 < r * r, r0 < 0.r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: le-lem, seq: ⊦ r < r0 ↔ ¬ r0 ≤ r, subst:[r, r0] → [r0 * r0, r * r], <all paths>

Additional information

Used terms: r0 * r0, r * r

Proof step 89 from proof square-le (previous step) (back to tree)

⊦ r < r0 ↔ ¬ r0 ≤ r

A spec-lemma

Proof step 90 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 < 0.r, r0 ≤ 0.r, ¬ r * r ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-abs, name: forward-lele, seq: ⊦ r ≤ r0 ∧ r0 ≤ r1 → r ≤ r1, subst:[r0, r, r1] → [r * ~ r0, r * r, r0 * r0], <all paths>

Additional information

Used terms: r * ~ r0, r * r, r0 * r0

Proof step 91 from proof square-le (previous step) (back to tree)

⊦ r ≤ r0 ∧ r0 ≤ r1 → r ≤ r1

A spec-lemma

Proof step 92 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 ≤ 0.r, r0 < 0.r, ¬ r * r ≤ r0 * r0 ⊦ r * r ≤ r * ~ r0 ∧ r * ~ r0 ≤ r0 * r0

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Proof step 93 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 < 0.r, r0 ≤ 0.r, ¬ r * r ≤ r * ~ r0, ¬ r * r ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: le-pos, seq: ⊦ 0.r < r → (r * r0 ≤ r * r1 ↔ r0 ≤ r1), subst:[r, r0, r1] → [r, r, ~ r0], <all paths>

Additional information

Used simplifier rules: ⊦ r ≤ ~ r0 ↔ r + r0 ≤ 0.r; (s) ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss) ⊦ r ≤ r0 → ¬ r0 < r; (s) Used terms: r, r, ~ r0

Proof step 94 from proof square-le (previous step) (back to tree)

⊦ 0.r < r → (r * r0 ≤ r * r1 ↔ r0 ≤ r1)

Lemma le-pos

Proof step 95 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 < 0.r, r0 ≤ 0.r, ¬ r * ~ r0 ≤ r0 * r0, ¬ r * r ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r0, r], <all paths>

Additional information

Used simplifier rules: mult-com: ⊦ r * r0 = r0 * r; Used terms: r0, r

Proof step 96 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 97 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 ≤ 0.r, r0 < 0.r, ¬ r * r ≤ r0 * r0, ¬ ~(r0 * r) ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: mult-com, seq: ⊦ r * r0 = r0 * r, subst:[r, r0] → [r0, r], <all paths>

Additional information

Used terms: r0, r

Proof step 98 from proof square-le (previous step) (back to tree)

⊦ r * r0 = r0 * r

Lemma mult-com

Proof step 99 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 < 0.r, r0 ≤ 0.r, ¬ r * r ≤ r0 * r0, ¬ ~(r * r0) ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: minus-left, seq: ⊦ ~ r * r0 = ~(r * r0), subst:[r, r0] → [r, r0], <rotated> <all paths>

Additional information

Used terms: r, r0

Proof step 100 from proof square-le (previous step) (back to tree)

⊦ ~ r * r0 = ~(r * r0)

Lemma minus-left

Proof step 101 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 ≤ 0.r, r0 < 0.r, ¬ r * r ≤ r0 * r0, ¬ ~ r * r0 ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: mult-com, seq: ⊦ r * r0 = r0 * r, subst:[r, r0] → [~ r, r0], <all paths>

Additional information

Used terms: ~ r, r0

Proof step 102 from proof square-le (previous step) (back to tree)

⊦ r * r0 = r0 * r

Lemma mult-com

Proof step 103 from proof square-le (previous step) (back to tree)

0.r ≠ r, 0.r < r, r + r0 ≤ 0.r, r0 < 0.r, r0 ≤ 0.r, ¬ r * r ≤ r0 * r0, ¬ r0 * ~ r ≤ r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: le-neg, seq: ⊦ r < 0.r → (r * r0 ≤ r * r1 ↔ r1 ≤ r0), subst:[r, r0, r1] → [r0, ~ r, r0], <all paths>

Additional information

Used simplifier rules: ⊦ r ≤ ~ r0 ↔ r + r0 ≤ 0.r; (s) ⊦ r ≤ r0 ↔ ¬ r0 < r; (ss) add-comm: ⊦ r + r0 = r0 + r; from specification real-basic ⊦ r ≤ r0 → ¬ r0 < r; (s) Used terms: r0, ~ r, r0

Proof step 104 from proof square-le (previous step) (back to tree)

⊦ r < 0.r → (r * r0 ≤ r * r1 ↔ r1 ≤ r0)

Lemma le-neg

Proof step 105 from proof square-le (previous step) (back to tree)

0.r ≤ (r0 < 0.r ⊃ ~ r0;r0), 0.r ≤ r, r ≤ r0, r0 * r0 < r * r, ¬ r0 < 0.r ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-lele: ⊦ r ≤ r0 ∧ r0 ≤ r1 → r ≤ r1; (forward) from specification real-abs ⊦ r ≤ r0 → ¬ r0 < r; (s)

Proof step 106 from proof square-le (previous step) (back to tree)

0.r ≤ r, 0.r ≤ r0, r ≤ r0, r0 * r0 < r * r ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: real-basic, name: trans-lem, seq:¬ r < r1, r < r0 ⊦ ¬ r0 < r1, subst:[r, r0, r1] → [r * r0, r0 * r0, r * r], <all paths>

Additional information

Used terms: r * r0, r0 * r0, r * r

Proof step 107 from proof square-le (previous step) (back to tree)

¬ r < r1, r < r0 ⊦ ¬ r0 < r1

A spec-lemma

Proof step 108 from proof square-le (previous step) (back to tree)

0.r ≤ r0, 0.r ≤ r, r ≤ r0, r0 * r0 < r * r ⊦ ¬ r * r0 < r * r ∧ r * r0 < r0 * r0

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Used simplifier rules: ls-forward: ⊦ r * r0 < r * r2 → r ≠ 0.r; ls-pos: ⊦ 0.r < r → (r * r0 < r * r2 ↔ r0 < r2); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r ≠ r0 → (r ≤ r0 ↔ r < r0); (s) ⊦ r ≤ r0 → ¬ r0 < r; (s)

Proof step 109 from proof square-le (previous step) (back to tree)

0.r ≤ r, 0.r ≤ r0, r ≤ r0, r0 * r0 < r * r, ¬ r * r0 < r0 * r0 ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: ls-pos-01, seq: ⊦ 0.r < r0 → (r * r0 < r1 * r0 ↔ r < r1), subst:[r, r0, r1] → [r, r0, r0], <all paths>

Additional information

Used simplifier rules: mult-zero: ⊦ 0.r * r = 0.r; mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ls-pos: ⊦ 0.r < r → (r * r0 < r * r2 ↔ r0 < r2); mult-ass: ⊦ (r * r0) * r1 = r * r0 * r1; mult-com: ⊦ r * r0 = r0 * r; ⊦ r < r0 ↔ ¬ r0 ≤ r; (ss) ⊦ r ≤ r0 → (r0 ≤ r ↔ r = r0); (s) lf-02: ⊦ r < r0 ∧ r0 = r1 → r < r1; (forward) from specification real-basic ⊦ r ≤ r0 → ¬ r0 < r; (s) ⊦ r ≤ 0.r ∧ 0.r ≤ r0 → r ≤ r0; (s) Used terms: r, r0, r0

Proof step 110 from proof square-le (previous step) (back to tree)

⊦ 0.r < r0 → (r * r0 < r1 * r0 ↔ r < r1)

Lemma ls-pos-01

Proof Tree for square-le (View conclusion)

The following image shows the proof tree of sequent calculus. The proved goal is at the bottom. You can click on the nodes to view additional rules. See here for details on colors in a proof tree.

the proof tree