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Theorem fun-neq

⊦ bf ≠ bf0 ↔ (∃ n. bf(n) ≠ bf0(n) ∧ (∀ n0. n0 < n → bf(n0) = bf0(n0)))

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: cont-relative-thm, cont-thm, conttr-relative-thm, conttr-thm,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 5
Proof steps: 8
Used lemmas:
Used spec theorems:
- Used simplifier rules:
  - nat-basic/f