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Proof step 1 from proof mapex-put (conclusion) (back to tree)

r ∈ rs ⊦ (r.=>_ * hR)[rs, f(r := o), g(r := a)] ↔ (r.==>(o, a) * hR)[rs, f(r := o), g(r := a)]

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information

Proof step 2 from proof mapex-put (previous step) (back to tree)

¬((r.=>_ * hR)[rs, f(r := o), g(r := a)] ↔ (r.==>(o, a) * hR)[rs, f(r := o), g(r := a)]), r ∈ rs ⊦

User applied rule apply rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel>, name: modifysep-def, seq: ⊦ hP[rs, f, g] ↔ hP[rs, λ r. (f(r), g(r))], subst:[hP, rs, f, g] → [r.=>_ * hR, rs, f(r := o), g(r := a)], <all paths>

Additional information

Used terms: r.=>_ * hR, rs, f(r := o), g(r := a)

Proof step 3 from proof mapex-put (previous step) (back to tree)

⊦ hP[rs, f, g] ↔ hP[rs, λ r. (f(r), g(r))]

Lemma modifysep-def

Proof step 4 from proof mapex-put (previous step) (back to tree)

¬((r.=>_ * hR)[rs, λ r0. (f(r := o)(r0), g(r := a)(r0))] ↔ (r.==>(o, a) * hR)[rs, f(r := o), g(r := a)]), r ∈ rs ⊦

User applied rule apply lemma

And obtained the following new goals

Rule argument

spec: heap-fun, name:mapex-put, seq:r ∈ rs ⊦ (r.=>_ * hP)[rs, f(r := o)] ↔ (r => o * hP)[rs, f(r := o)], subst:[rs, r, o, f, hP] → [rs, r, (o, a), λ r0. (f(r := o)(r0), g(r := a)(r0)), hR]; [A] → [(A, B)]

Additional information

Used terms: rs, r, (o, a), λ r0. (f(r := o)(r0), g(r := a)(r0)), hR

Proof step 5 from proof mapex-put (previous step) (back to tree)

r ∈ rs ⊦ (r.=>_ * hP)[rs, f(r := o)] ↔ (r => o * hP)[rs, f(r := o)]

A spec-lemma

Proof step 6 from proof mapex-put (previous step) (back to tree)

(r.=>_ * hR)[rs, (λ r0. (f(r := o)(r0), g(r := a)(r0)))(r := (o, a))] ↔ (r => (o, a) * hR)[rs, (λ r0. (f(r := o)(r0), g(r := a)(r0)))(r := (o, a))], ¬((r.=>_ * hR)[rs, λ r0. (f(r := o)(r0), g(r := a)(r0))] ↔ (r.==>(o, a) * hR)[rs, f(r := o), g(r := a)]), r ∈ rs ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: maplet-def: ⊦ r.==>(o, a) = r => (o, a); modifysep-def: ⊦ hP[rs, f, g] ↔ hP[rs, λ r. (f(r), g(r))]; ⊦ (r.=>_ * hP)[rs, f] → r ∈ rs; (s) sep-com: ⊦ hP0 * hP1 = hP1 * hP0; from specification heap-sep sep-ass: ⊦ (hP0 * hP1) * hP2 = hP0 * hP1 * hP2; from specification heap-sep ⊦ (r => o * hP)[rs, f] → (r.=>_ * hP)[rs, f]; (s)

Proof step 7 from proof mapex-put (previous step) (back to tree)

(r.=>_ * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))], ¬ (r => (o, a) * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))], (r.=>_ * hR)[rs, λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))] → (r => (o, a) * hR)[rs, λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))] ⊦

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 3

Additional information

Proof step 8 from proof mapex-put (previous step) (back to tree)

(r.=>_ * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))], ¬ (r.=>_ * hR)[rs, λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))], ¬ (r => (o, a) * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))] ⊦

User applied rule decompose

And obtained the following new goals

Rule argument

poslist: left 1, left 2

Additional information

Proof step 9 from proof mapex-put (previous step) (back to tree)

(λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))) ≠ (λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))), (r.=>_ * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))], ¬ (r => (o, a) * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Proof step 10 from proof mapex-put (previous step) (back to tree)

((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0))) ≠ (r0 = r ⊃ (o, a);(f(r0), g(r0))), (r.=>_ * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))], ¬ (r => (o, a) * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))] ⊦

User applied rule case distinction

And closed the goal!

Rule argument

pos: left 1

Additional information

Proof step 11 from proof mapex-put (previous step) (back to tree)

(r.=>_ * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))], (r => (o, a) * hR)[rs, λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))], ¬ (r => (o, a) * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))] ⊦

User applied rule decompose

And obtained the following new goals

Rule argument

poslist: left 2, left 3

Additional information

Proof step 12 from proof mapex-put (previous step) (back to tree)

(λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))) ≠ (λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))), (r => (o, a) * hR)[rs, λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))], (r.=>_ * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Proof step 13 from proof mapex-put (previous step) (back to tree)

(r1 = r ⊃ (o, a);(f(r1), g(r1))) ≠ ((r = r1 ⊃ o;f(r1)), (r = r1 ⊃ a;g(r1))), (r.=>_ * hR)[rs, λ r0. ((r = r0 ⊃ o;f(r0)), (r = r0 ⊃ a;g(r0)))], (r => (o, a) * hR)[rs, λ r1. (r1 = r ⊃ (o, a);(f(r1), g(r1)))] ⊦

User applied rule case distinction

And closed the goal!

Rule argument

pos: left 1

Additional information

Proof Tree for mapex-put (View conclusion)

The following image shows the proof tree of sequent calculus. The proved goal is at the bottom. You can click on the nodes to view additional rules. See here for details on colors in a proof tree.

the proof tree