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Theorem Decl-allocjsiz

¬ null ∈ h, ¬ null ∈ h0 ⊦ ⟨r := alloc#(; h)⟩ (h = h0 ∧ r = r0) ↔ ⟨r := choose r0 with ¬ r0 ∈ h ∧ r0 ≠ null in {h := h +h r0; r0} ifnone null⟩ (h = h0 ∧ r = r0)

Type: A proof obligation
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes

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Infos about the proof

Proved?: Yes
Interactions: 5
Proof steps: 36
Used lemmas:
Used spec theorems:
- Used simplifier rules:
  - heapmap/add-in