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Theorem get-assign

⊦ h1 ≡ h0(r := o) ∧ r ≠ r0 ∧ r0 ∈ h1 → h0(r0) = h1(r0)

Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by: assigned-known-getother2,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 0
Proof steps: 2
Used lemmas: eq,
Used spec theorems:
- Used simplifier rules:
  - map/At-other