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Theorem base for Specification tidset-npset

This is a listing of all goals defined over the current specification. Axioms are marked yellow, proved theorems green and unproved theorems blue. Click on individual names to get more information on the proof.

Name: Sequent: Type:
union-def ⊦ sa1 ∪ sa2 = sa1 ⊕ sa2 An Axiom
bigunion-get ⊦ alldisjointp(ts, f) ∧ np ∈ f(tid) → U(ts, f)[np] = f(tid)[np] An Axiom
bigunion-in ⊦ alldisjointp(ts, f) → (np ∈ U(ts, f) ↔ (∃ tid. tid ∈ ts ∧ np ∈ f(tid))) An Axiom
alldisjointp-def ⊦ alldisjointp(ts, f) ↔ (∀ tid1, tid2, np. tid1 ∈ ts ∧ tid2 ∈ ts ∧ np ∈ f(tid1) ∧ tid1 ≠ tid2 → ¬ np ∈ f(tid2)) An Axiom
disjointp-def ⊦ disjointp(sa1, sa2) ↔ (∀ np. np ∈ sa1 → ¬ np ∈ sa2) An Axiom
alldisjointp-reduce⊦ alldisjointp(ts, f) → ( alldisjointp(ts, f0) ↔ (∀ tid1, tid2, np. (tid1 ∈ ts ∧ tid2 ∈ ts ∧ tid1 ≠ tid2 ∧ np ∈ f(tid1) → ¬ np ∈ f(tid2)) → tid1 ∈ ts ∧ tid2 ∈ ts ∧ tid1 ≠ tid2 ∧ np ∈ f0(tid1) → ¬ np ∈ f0(tid2))) A User Theorem
disjoint-empty-l ⊦ disjointp(∅, spmx1) A User Theorem
disjoint-empty-r ⊦ disjointp(spmx1, ∅) A User Theorem
disjointp-reduce ⊦ disjointp(spmx1, spmx2) → (disjointp(spmx3, spmx4) ↔ (∀ np. (np ∈ spmx1 → ¬ np ∈ spmx2) → np ∈ spmx3 → ¬ np ∈ spmx4)) A User Theorem
in-union ⊦ np ∈ spmx1 ∪ spmx2 ↔ np ∈ spmx1 ∨ np ∈ spmx2 A User Theorem
union-empty-l ⊦ ∅ ∪ spmx = spmx A User Theorem
union-empty-r ⊦ spmx ∪ ∅ = spmx A User Theorem
union-lookup ⊦ (spmx1 ∪ spmx2)[np] = (np ∈ spmx1 ⊃ spmx1[np];spmx2[np]) A User Theorem
union-subset ⊦ disjointp(spmx1, spmx2) → (spmx1 ∪ spmx2 ⊆ spmx ↔ spmx1 ⊆ spmx ∧ spmx2 ⊆ spmx) A User Theorem