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Theorem subarray-copy-higher
m0 + m1 ≤ n1, m0 + m1 ≤ # ar ⊦ subarray(copy(ar0, n0, ar, n1, n2), m0, m1) = subarray(ar, m0, m1)
Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by:
Used by units in proved state:
list-as-arrayinstance
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 4
Proof steps: 8
Used lemmas:
at-copy
,
size-copy
,
Subarray
,
Used spec theorems:
array
/
Extension
Used simplifier rules:
nat-basic
/
f
array
/
Size-mkarray
nat
/
lels
nat
/
ls-le-simp
nat
/
sub-base
nat-basic
/
c
nat-basic
/
a
nat-basic
/
add-base
nat-basic
/
less-zero
nat
/
let
nat
/
lep-02
nat
/
add-01
nat
/
le-def
nat
/
fle-01
nat-basic
/
l-01