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Proof step 1 from proof div-mult-pos-02 (conclusion) (back to tree)

⊦ 0 < j ∧ 0 ≤ i ∧ 0 ≤ i0 ∧ i0 < j → (i * j + i0) / j = i

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information

Proof step 2 from proof div-mult-pos-02 (previous step) (back to tree)

(i * j + i0) / j ≠ i, 0 < j, i0 < j, 0 ≤ i, 0 ≤ i0 ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-mult-pos: ⊦ 0 < j ∧ 0 ≤ i ∧ 0 ≤ i0 ∧ i0 < j → (j * i + i0) / j = i; add-c: ⊦ i + j = j + i; from specification int-basic2 add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2 commutativity: ⊦ i * j = j * i; from specification int-mult associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult

Proof Tree for div-mult-pos-02 (View conclusion)

The following image shows the proof tree of sequent calculus. The proved goal is at the bottom. You can click on the nodes to view additional rules. See here for details on colors in a proof tree.

the proof tree