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Theorem eq-01

⊦ m + n = m + n0 ↔ n = n0

Type: A user defined theorem
Validity: The proof is valid.
Features: s, ls,
Comment:
Used by: addex, elim-pred-c, eq-02, eqs, even, even-02, even-06, ex-oddeven, l, l-03, less, less-03, neq-03, pe, pe-01, pred, ps, psh-03, psh-04, q-add, q-add-01, s-04,
Used by units in proved state: list-del, list+array-ops, olist-sort, list-as-arrayinstance, rowcol-upd, olist, filter-count, array-copy, mon-lim-filter-count, list, assoclist, bag-basic, stut-mon, set-basic, nat-div, nat-mult, stream, nat, nat-prime, list-perm, string-less, list-data, set-union, bag-union, choice, list-set, nat-inf, inf-app-list, intnat, infinite-append, nat-pair, nat-pot, list-dup, store, nat-even, list-last, array-revin, list-getput,
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 0
Proof steps: 5
Used lemmas: inj-succ, rec, c, a, z-02, gen,
Used spec theorems:
- Used simplifier rules: