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Theorem base for Specification nat-pot

This is a listing of all goals defined over the current specification. Axioms are marked yellow, proved theorems green and unproved theorems blue. Click on individual names to get more information on the proof.

Name: Sequent: Type:
Pot-zero ⊦ n ^ 0 = 1 An Axiom
Pot2-zero ⊦ 2^ 0 = 1 An Axiom
Log2def ⊦ 2^ m ≤ n ∧ n < 2^ m +1 → log2 n = m An Axiom
Pot-succ ⊦ n ^ m +1 = n ^ m * n An Axiom
Pot2-succ ⊦ 2^ n +1 = 2 * 2^ n An Axiom
Logdef ⊦ m ^ n0 ≤ n ∧ n < m ^ n0 +1 → log(m, n) = n0 An Axiom
2-pot-mod ⊦ m ≠ 0 → 2 ^ m % 2 = 0 A User Theorem
2-pot-mod-01 ⊦ 2 ^ m ≠ 1 → 2 ^ m % 2 = 0 A User Theorem
add ⊦ m ^ (n + n0) = m ^ n * m ^ n0 A User Theorem
div-eq-zerom0 ≠ 0 ⊦ n0 / m0 = 0 ↔ n0 < m0 A User Theorem
inj ⊦ 2^ n = 2^ m ↔ n = m A User Theorem
inj-02 ⊦ 2^ n = 2 * 2^ m ↔ n = m + 1 A User Theorem
laddm ≠ 0 ⊦ ¬ log2(m + n) < log2 m A User Theorem
ladd-01n ≠ 0 ⊦ m = n + n0 → ¬ log2 m < log2 n A User Theorem
lemma-ax2 ⊦ 2^(n + 1) = 2 * 2^ n A User Theorem
lls ⊦ n ≠ 0 → ¬ n < 2^ log2 n A User Theorem
lls-01 ⊦ n < 2^(log2 n + 1) A User Theorem
lls-02n ≠ 0 ⊦ log2 m < log2 n → m < n A User Theorem
log2-elimm ≠ 0 ⊦ n = log2 m ↔ (∃ m0. m = 2^ n + m0 ∧ m0 < 2^ n) A User Theorem
lone ⊦ log2 1 = 0 A User Theorem
lpot ⊦ log2 2^ n = n A User Theorem
lsucc-01 ⊦ n ≠ 0 → log2(2 * n + 1) = log2 n + 1 A User Theorem
ltwo-03 ⊦ n ≠ 0 → log2(2 * n) = log2 n + 1 A User Theorem
ltwo-04 ⊦ log2 2 = 1 A User Theorem
ltwo-05 ⊦ n < 2 * 2^ log2 n A User Theorem
lzer ⊦ log2(m + 1) = 0 ↔ m = 0 A User Theorem
mult ⊦ (m * m0) ^ n = m ^ n * m0 ^ n A User Theorem
one ⊦ 2^ m = 1 ↔ m = 0 A User Theorem
one-01 ⊦ 2^ 1 = 2 A User Theorem
one-01-01 ⊦ m ^ 1 = m A User Theorem
one-02 ⊦ 0 ^ 1 = 0 A User Theorem
pot-01n ≠ 0 ⊦ 2 * 2^ n -1 = 2^ n A User Theorem
pot-mon1 < m ⊦ m ^ n < m ^ n0 ↔ n < n0 A User Theorem
pot-two ⊦ m ^ 2 = m * m A User Theorem
pot-zero ⊦ m ≠ 0 → m ^ n ≠ 0 A User Theorem
pot-zero-01 ⊦ n ≠ 0 → 0 ^ n = 0 A User Theorem
pot2-add ⊦ 2^(m + n) = 2^ m * 2^ n A User Theorem
pot2-def ⊦ 2^ m = 2 ^ m A User Theorem
potexn ≠ 0 ⊦ ∃ m. 2^ m ≤ n ∧ n < 2^(m + 1) A User Theorem
potmon ⊦ 2^ m < 2^ n ↔ m < n A User Theorem
potmonleq ⊦ 2^ m ≤ 2^ n ↔ m ≤ n A User Theorem
power-of-2 ⊦ 2 ^ m ≠ 1 → 2 * 2 ^ m / 2 = 2 ^ m A User Theorem
power-of-2-01 ⊦ 2 ^ m ≠ 1 → 4 * 2 ^ m / 2 * n = 2 * n * 2 ^ m A User Theorem
rec ⊦ 2^(n + 1) = 2^ n + 2^ n A User Theorem
rec-01 ⊦ n ^ (m + 1) = n ^ m * n A User Theorem
succ-02 ⊦ 2 * 2^ m = 2^(m + 1) A User Theorem
succ-03 ⊦ 2^ m = 2 * n + 1 ↔ m = 0 ∧ n = 0 A User Theorem
two ⊦ m ^ (2 * n) = m ^ n * m ^ n A User Theorem
two-pot-zero ⊦ 2 ^ n ≠ 0 A User Theorem
zero ⊦ 2^ n ≠ 0 A User Theorem
zero-01 ⊦ 0 ^ n = 0 ↔ n ≠ 0 A User Theorem