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Theorem base for Specification set-basic

This is a listing of all goals defined over the current specification. Axioms are marked yellow, proved theorems green and unproved theorems blue. Click on individual names to get more information on the proof.

Name: Sequent: Type:
sub-insert-3 ⊦ s0 ++ a0 ⊆ s1 ++ a0 ++ a1 ++ a2 ↔ s0 ⊆ s1 ++ a0 ++ a1 ++ a2 A User Theorem
size-three-01 ⊦ a ∈ s ∧ b ∈ s ∧ c ∈ s ∧ a ≠ b ∧ a ≠ c ∧ b ≠ c → 3 ≤ # s A User Theorem
size-zero-03 ⊦ s = ∅ → # s = 0 A User Theorem
subset-insert-same ⊦ s ++ a ⊆ s0 ++ a ↔ s ⊆ s0 ++ a A User Theorem
size-less ⊦ ¬ # s + 1 < #(s ++ a) A User Theorem
size-less-01 ⊦ ¬ #(s ++ a) < # s A User Theorem
ext-rec ⊦ s1 = s0 ++ a ↔ (∀ b. b ∈ s1 ↔ b = a ∨ b ∈ s0) A User Theorem
subset-insert-01 ⊦ s ⊆ s ++ a ++ a0 ++ b ++ c A User Theorem
size-two-05 ⊦ # s = 2 ↔ (∃ a, b. a ≠ b ∧ s = ∅ ++ a ++ b ∧ a ∈ s ∧ b ∈ s) A User Theorem
add-01 ⊦ s ++ a ++ a = s ++ a A User Theorem
sw ⊦ s ++ b ++ a = s ++ a ++ b A User Theorem
eq ⊦ a ∈ s → s ++ a = s A User Theorem
ne-02 ⊦ a ∈ s → (s = ∅ ↔ false) A User Theorem
one ⊦ (∀ a. a ∈ s → a = b) ∧ s ≠ ∅ → s = ∅ ++ b A User Theorem
genset generated by ∅, ++; An Axiom
eqtwo ⊦ ∅ ++ a ++ b = ∅ ++ a ++ c ↔ b = c A User Theorem
two-01a ∈ s, s ≠ ∅ ++ a ⊦ ∃ b. b ∈ s ∧ b ≠ a A User Theorem
sub-add-02 ⊦ s ++ a ⊆ s0 → s ⊆ s0 A User Theorem
in-05 ⊦ s ++ a = s0 ++ b ∧ a ≠ b → a ∈ s0 A User Theorem
Extension ⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) An Axiom
sub-add ⊦ a ∈ s0 → (s ++ a ⊆ s0 ↔ s ⊆ s0) A User Theorem
sub-one-01 ⊦ s ≠ ∅ ++ a → (s ⊆ ∅ ++ a ↔ s = ∅) A User Theorem
subset-insert ⊦ s ⊆ s ++ a ++ b ++ c A User Theorem
size-zero-02 ⊦ # s = 0 → s = ∅ A User Theorem
sub-size ⊦ s ⊆ s0 → ¬ # s0 < # s A User Theorem
eq-06 ⊦ ∅ ++ a ++ b = ∅ ++ b ++ a A User Theorem
sub-two ⊦ ∅ ++ a ++ b ⊆ ∅ ++ c ↔ a = b ∧ a = c A User Theorem
subset-equal ⊦ s ⊆ s0 → (s0 ⊆ s ↔ s = s0) A User Theorem
size-two-04 ⊦ # s ≠ 0 ∧ # s ≠ 1 ∧ a ∈ s → (∃ b. b ∈ s ∧ a ≠ b) A User Theorem
subset-insert-03 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ b ++ c A User Theorem
sizesub ⊦ s ⊆ s0 → # s ≤ # s0 A User Theorem
in-02 ⊦ a ≠ b → (a ∈ s ++ b ↔ a ∈ s) A User Theorem
In-insert ⊦ a ∈ s ++ b ↔ a = b ∨ a ∈ s An Axiom
sub-insert-5 ⊦ s0 ++ a0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 ↔ s0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 A User Theorem
eq-03 ⊦ s ++ a = s ↔ a ∈ s A User Theorem
subset-insert-06 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 ++ a5 ++ b ++ c A User Theorem
size-ins ⊦ # s + 1 = #(s ++ a) ↔ ¬ a ∈ s A User Theorem
size-two-01 ⊦ #(∅ ++ a ++ b) = 2 ↔ a ≠ b A User Theorem
addtwo ⊦ s ++ a ++ b ++ a = s ++ b ++ a A User Theorem
selsize ⊦ # s ≠ 0 → (∃ a. a ∈ s) A User Theorem
sub-ntrans-01 ⊦ s0 ⊆ s1 ∧ ¬ s ⊆ s1 → ¬ s ⊆ s0 A User Theorem
eqtwo-01 ⊦ ∅ ++ a ++ b = ∅ ++ c ++ b ↔ a = c A User Theorem
sizesubl ⊦ s ⊆ s0 ∧ a ∈ s0 ∧ ¬ a ∈ s → # s < # s0 A User Theorem
size-one-03 ⊦ # s = 1 ↔ (∃ a. s = ∅ ++ a) A User Theorem
sub-e ⊦ ∅ ⊆ s A User Theorem
subset-ins ⊦ s ++ a ⊆ s0 ++ a ++ b ↔ s ⊆ s0 ++ a ++ b A User Theorem
sub-insert ⊦ ¬ a ∈ s → (s ⊆ s0 ++ a ↔ s ⊆ s0) A User Theorem
ins-two ⊦ a ∈ s → s ++ b ++ a = s ++ b A User Theorem
sub-one ⊦ s ≠ ∅ ∧ # s0 = 1 → (s ⊆ s0 ↔ s = s0) A User Theorem
one-in ⊦ # s = 1 ∧ a ∈ s → s = ∅ ++ a A User Theorem
Size-insert ⊦ ¬ a ∈ s → #(s ++ a) = # s + 1 An Axiom
sub-add-01 ⊦ s ⊆ s ++ a A User Theorem
subset-empty ⊦ s ⊆ ∅ ↔ s = ∅ A User Theorem
sub-sizeneqexs ⊆ s0, # s ≠ # s0 ⊦ ∃ a. a ∈ s0 ∧ ¬ a ∈ s A User Theorem
sub-size-eq ⊦ s ⊆ s0 → (# s0 ≤ # s ↔ s = s0) A User Theorem
in-04 ⊦ a ∈ ∅ ++ b ↔ a = b A User Theorem
subset ⊦ s ⊆ s ++ a ++ b A User Theorem
size-two ⊦ # s = 2 ↔ (∃ a, b. a ≠ b ∧ s = ∅ ++ a ++ b) A User Theorem
ne-01 ⊦ a ∈ s → s ≠ ∅ A User Theorem
Subset ⊦ s1 ⊆ s2 ↔ (∀ a. a ∈ s1 → a ∈ s2) An Axiom
subset-insert-05 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 ++ b ++ c A User Theorem
in ⊦ a ∈ s → a ∈ s ++ b A User Theorem
In-empty ⊦ ¬ a ∈ ∅ An Axiom
size-two-031 < # s ⊦ ∃ a, b. a ≠ b ∧ a ∈ s ∧ b ∈ s A User Theorem
size-zero-01 ⊦ s ≠ ∅ → # s ≠ 0 A User Theorem
eq-05 ⊦ ∅ ++ a ++ b = ∅ ++ b ++ a ↔ true A User Theorem
sub-insert-01 ⊦ s ⊆ s0 → s ⊆ s0 ++ a A User Theorem
sub-add-04 ⊦ s1 ⊆ s2 → s1 ++ a ⊆ s2 ++ a A User Theorem
sub-insert-4 ⊦ s0 ++ a0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 ↔ s0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 A User Theorem
in-01 ⊦ a ∈ s ++ a A User Theorem
size-zero ⊦ # s ≠ 0 → s ≠ ∅ A User Theorem
size-three-02 ⊦ # s = 3 ↔ (∃ a, b, c. a ≠ b ∧ a ≠ c ∧ b ≠ c ∧ s = ∅ ++ a ++ b ++ c) A User Theorem
subset-insert-02 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ b ++ c A User Theorem
size-two-06 ⊦ a ∈ s ∧ b ∈ s ∧ a ≠ b → 2 ≤ # s A User Theorem
sw-01 ⊦ s ++ a ++ b ++ c = s ++ c ++ a ++ b A User Theorem
indef ⊦ a ∈ s ↔ (∃ s0. s = s0 ++ a ∧ ¬ a ∈ s0) A User Theorem
eq-02 ⊦ ¬ a ∈ s → (s ++ a = ∅ ++ b ↔ a = b ∧ s = ∅) A User Theorem
sub-ntrans ⊦ s ⊆ s0 ∧ ¬ s ⊆ s1 → ¬ s0 ⊆ s1 A User Theorem
subsize-eq ⊦ s ⊆ s0 ∧ # s = # s0 → s = s0 A User Theorem
one-size ⊦ s = ∅ ++ a → # s = 1 A User Theorem
sub-in ⊦ a ∈ s ∧ s ⊆ s0 → a ∈ s0 A User Theorem
sel ⊦ s = ∅ ∨ (∃ a. a ∈ s) A User Theorem
sub-add-03 ⊦ s ++ a ⊆ s0 ↔ s ⊆ s0 ∧ a ∈ s0 A User Theorem
size-one-02 ⊦ # s = 1 ∧ a ∈ s ∧ b ∈ s → a = b A User Theorem
dela ∈ s ⊦ ∃ s0. s = s0 ++ a ∧ ¬ a ∈ s0 A User Theorem
ne ⊦ ∅ ≠ s ++ a A User Theorem
alle∀ a. ¬ a ∈ s ⊦ s = ∅ A User Theorem
sub-one-02 ⊦ ∅ ++ a ⊆ s ↔ a ∈ s A User Theorem
size-exgr# s < # s0 ⊦ ∃ a. a ∈ s0 ∧ ¬ a ∈ s A User Theorem
eq-01 ⊦ ¬ a ∈ s ∧ ¬ a ∈ s0 → (s ++ a = s0 ++ a ↔ s = s0) A User Theorem
two ⊦ a ≠ a0 → (∅ ++ a ++ b = ∅ ++ a0 ++ c ↔ a = c ∧ b = a0) A User Theorem
subset-insert-04 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ a3 ++ b ++ c A User Theorem
in-03 ⊦ ¬ a ∈ s → (a ∈ s ++ b ↔ a = b) A User Theorem
add ⊦ a ∈ s ++ b ↔ ¬(a ≠ b ∧ ¬ a ∈ s) A User Theorem
subsize-eq-01 ⊦ # s = # s0 → (s ⊆ s0 ↔ s = s0) A User Theorem
sub-trans ⊦ s ⊆ s0 ∧ s0 ⊆ s1 → s ⊆ s1 A User Theorem
in-06 ⊦ a ∈ s ∧ s = ∅ ++ b → a = b A User Theorem
size-two-02 ⊦ #(∅ ++ a ++ b) ≤ 2 A User Theorem
eq-subset ⊦ s = s0 ↔ s ⊆ s0 ∧ s0 ⊆ s A User Theorem
addthree ⊦ s ++ a ++ b ++ c ++ a = s ++ a ++ b ++ c A User Theorem
size-one ⊦ # s = 1 → (∃ a. s = ∅ ++ a) A User Theorem
size-one-01 ⊦ #(∅ ++ a) = 1 A User Theorem
sub-idem ⊦ s ⊆ s A User Theorem
size-three ⊦ 2 < # s → (∃ a, b, c. a ∈ s ∧ b ∈ s ∧ c ∈ s ∧ a ≠ b ∧ a ≠ c ∧ b ≠ c) A User Theorem
Size-empty ⊦ # ∅ = 0 An Axiom
eq-04 ⊦ s ++ b ++ a = s ++ a ++ b ↔ true A User Theorem