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Proof step 1 from proof len-app (conclusion) (back to tree)

⊦ #(str + str0) = # str + # str0

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information

Proof step 2 from proof len-app (previous step) (back to tree)

#(str + str0) ≠ # str + # str0 ⊦

User applied rule structural induction

And obtained the following new goals

Rule argument

indvar: str

Additional information

Used simplifier rules: string freely generated by "", +;; ⊦ "" + x = x; (s) a: ⊦ (x + y) + z = x + y + z; from specification list[string] ⊦ # "" = 0; (s) ⊦ n + 0 = n; (s) a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic c: ⊦ m + n = n + m; from specification nat-basic

Proof step 3 from proof len-app (previous step) (back to tree)

#((char + str1) + str0) ≠ #(char + str1) + # str0, ∀ str0. #(str1 + str0) = # str1 + # str0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic ⊦ m + n = m + n0 ↔ n = n0; (s) a: ⊦ (x + y) + z = x + y + z; from specification list[string] ⊦ m +1 = m + 1; (s) ⊦ #(a ' + x) = (# x)+1; (s) ⊦ a + x = a ' + x; (s)

Proof step 4 from proof len-app (previous step) (back to tree)

#(str1 + str0) ≠ # str1 + # str0, ∀ str0. #(str1 + str0) = # str1 + # str0 ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: str0

Additional information

Used terms: str0

Proof Tree for len-app (View conclusion)

The following image shows the proof tree of sequent calculus. The proved goal is at the bottom. You can click on the nodes to view additional rules. See here for details on colors in a proof tree.

the proof tree