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Theorem base for Specification infset-basic

This is a listing of all goals defined over the current specification. Axioms are marked yellow, proved theorems green and unproved theorems blue. Click on individual names to get more information on the proof.

Name: Sequent: Type:
sub-insert-3 ⊦ s0 ++ a0 ⊆ s1 ++ a0 ++ a1 ++ a2 ↔ s0 ⊆ s1 ++ a0 ++ a1 ++ a2 A User Theorem
subset-insert-same ⊦ s ++ a ⊆ s0 ++ a ↔ s ⊆ s0 ++ a A User Theorem
ext-rec ⊦ s1 = s0 ++ a ↔ (∀ b. b ∈ s1 ↔ b = a ∨ b ∈ s0) A User Theorem
subset-insert-01 ⊦ s ⊆ s ++ a ++ a0 ++ b ++ c A User Theorem
add-01 ⊦ s ++ a ++ a = s ++ a A User Theorem
sw ⊦ s ++ b ++ a = s ++ a ++ b A User Theorem
eq ⊦ a ∈ s → s ++ a = s A User Theorem
one ⊦ (∀ a. a ∈ s → a = b) ∧ s ≠ ∅ → s = ∅ ++ b A User Theorem
ne-02 ⊦ a ∈ s → (s = ∅ ↔ false) A User Theorem
geniset('a) generated by { }; An Axiom
eqtwo ⊦ ∅ ++ a ++ b = ∅ ++ a ++ c ↔ b = c A User Theorem
two-01a ∈ s, s ≠ ∅ ++ a ⊦ ∃ b. b ∈ s ∧ b ≠ a A User Theorem
sub-add-02 ⊦ s ++ a ⊆ s0 → s ⊆ s0 A User Theorem
in-05 ⊦ s ++ a = s0 ++ b ∧ a ≠ b → a ∈ s0 A User Theorem
sub-one-01 ⊦ s ≠ ∅ ++ a → (s ⊆ ∅ ++ a ↔ s = ∅) A User Theorem
sub-add ⊦ a ∈ s0 → (s ++ a ⊆ s0 ↔ s ⊆ s0) A User Theorem
Extension ⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) An Axiom
subset-insert ⊦ s ⊆ s ++ a ++ b ++ c A User Theorem
eq-06 ⊦ ∅ ++ a ++ b = ∅ ++ b ++ a A User Theorem
subset-equal ⊦ s ⊆ s0 → (s0 ⊆ s ↔ s = s0) A User Theorem
sub-two ⊦ ∅ ++ a ++ b ⊆ ∅ ++ c ↔ a = b ∧ a = c A User Theorem
subset-insert-03 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ b ++ c A User Theorem
in-02 ⊦ a ≠ b → (a ∈ s ++ b ↔ a ∈ s) A User Theorem
In-insert ⊦ a ∈ s ++ b ↔ a = b ∨ a ∈ s An Axiom
sub-insert-5 ⊦ s0 ++ a0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 ↔ s0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 A User Theorem
eq-03 ⊦ s ++ a = s ↔ a ∈ s A User Theorem
subset-insert-06 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 ++ a5 ++ b ++ c A User Theorem
addtwo ⊦ s ++ a ++ b ++ a = s ++ b ++ a A User Theorem
sub-ntrans-01 ⊦ s0 ⊆ s1 ∧ ¬ s ⊆ s1 → ¬ s ⊆ s0 A User Theorem
eqtwo-01 ⊦ ∅ ++ a ++ b = ∅ ++ c ++ b ↔ a = c A User Theorem
sub-e ⊦ ∅ ⊆ s A User Theorem
subset-ins ⊦ s ++ a ⊆ s0 ++ a ++ b ↔ s ⊆ s0 ++ a ++ b A User Theorem
sub-insert ⊦ ¬ a ∈ s → (s ⊆ s0 ++ a ↔ s ⊆ s0) A User Theorem
ins-two ⊦ a ∈ s → s ++ b ++ a = s ++ b A User Theorem
sub-add-01 ⊦ s ⊆ s ++ a A User Theorem
subset-empty ⊦ s ⊆ ∅ ↔ s = ∅ A User Theorem
subset ⊦ s ⊆ s ++ a ++ b A User Theorem
in-04 ⊦ a ∈ ∅ ++ b ↔ a = b A User Theorem
ne-01 ⊦ a ∈ s → s ≠ ∅ A User Theorem
Subset ⊦ s1 ⊆ s2 ↔ (∀ a. a ∈ s1 → a ∈ s2) An Axiom
subset-insert-05 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ a3 ++ a4 ++ b ++ c A User Theorem
In-empty ⊦ ¬ a ∈ ∅ An Axiom
in ⊦ a ∈ s → a ∈ s ++ b A User Theorem
eq-05 ⊦ ∅ ++ a ++ b = ∅ ++ b ++ a ↔ true A User Theorem
sub-add-04 ⊦ s1 ⊆ s2 → s1 ++ a ⊆ s2 ++ a A User Theorem
sub-insert-01 ⊦ s ⊆ s0 → s ⊆ s0 ++ a A User Theorem
sub-insert-4 ⊦ s0 ++ a0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 ↔ s0 ⊆ s1 ++ a0 ++ a1 ++ a2 ++ a3 A User Theorem
in-01 ⊦ a ∈ s ++ a A User Theorem
construct-set ⊦ a ∈ {f} ↔ f(a) An Axiom
subset-insert-02 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ b ++ c A User Theorem
sw-01 ⊦ s ++ a ++ b ++ c = s ++ c ++ a ++ b A User Theorem
indef ⊦ a ∈ s ↔ (∃ s0. s = s0 ++ a ∧ ¬ a ∈ s0) A User Theorem
expand ⊦ ∃ f. s = {f} A User Theorem
eq-02 ⊦ ¬ a ∈ s → (s ++ a = ∅ ++ b ↔ a = b ∧ s = ∅) A User Theorem
sub-ntrans ⊦ s ⊆ s0 ∧ ¬ s ⊆ s1 → ¬ s0 ⊆ s1 A User Theorem
sub-in ⊦ a ∈ s ∧ s ⊆ s0 → a ∈ s0 A User Theorem
sub-add-03 ⊦ s ++ a ⊆ s0 ↔ s ⊆ s0 ∧ a ∈ s0 A User Theorem
sel ⊦ s = ∅ ∨ (∃ a. a ∈ s) A User Theorem
ne ⊦ ∅ ≠ s ++ a A User Theorem
dela ∈ s ⊦ ∃ s0. s = s0 ++ a ∧ ¬ a ∈ s0 A User Theorem
sub-one-02 ⊦ ∅ ++ a ⊆ s ↔ a ∈ s A User Theorem
alle∀ a. ¬ a ∈ s ⊦ s = ∅ A User Theorem
two ⊦ a ≠ a0 → (∅ ++ a ++ b = ∅ ++ a0 ++ c ↔ a = c ∧ b = a0) A User Theorem
eq-01 ⊦ ¬ a ∈ s ∧ ¬ a ∈ s0 → (s ++ a = s0 ++ a ↔ s = s0) A User Theorem
subset-insert-04 ⊦ s ⊆ s ++ a ++ a0 ++ a1 ++ a2 ++ a3 ++ b ++ c A User Theorem
in-03 ⊦ ¬ a ∈ s → (a ∈ s ++ b ↔ a = b) A User Theorem
add ⊦ a ∈ s ++ b ↔ ¬(a ≠ b ∧ ¬ a ∈ s) A User Theorem
sub-trans ⊦ s ⊆ s0 ∧ s0 ⊆ s1 → s ⊆ s1 A User Theorem
characteristic-function ⊦ χ(s)(a) ↔ a ∈ s An Axiom
in-06 ⊦ a ∈ s ∧ s = ∅ ++ b → a = b A User Theorem
eq-subset ⊦ s = s0 ↔ s ⊆ s0 ∧ s0 ⊆ s A User Theorem
addthree ⊦ s ++ a ++ b ++ c ++ a = s ++ a ++ b ++ c A User Theorem
sub-idem ⊦ s ⊆ s A User Theorem
eq-04 ⊦ s ++ b ++ a = s ++ a ++ b ↔ true A User Theorem