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Theorem sublist-prefix
⊦ n ≤ n1 ∧ n1 + m0 < # x → (sublist(m0, n + 1, x) ⊑ sublist(m0, n1 + 1, x) ↔ true)
Type: A user defined theorem
Validity: The proof is valid.
Features: ss, lss,
Comment:
Used by:
Used by units in proved state:
wolist
,
olist
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 3
Proof steps: 13
Used lemmas:
restN-rec
,
restn-apprec
,
rest-rest1
,
first-num
,
firstN-zero
,
firstN-rec
,
sublist-def
,
Used spec theorems:
Used simplifier rules:
list-data
/
l
nat-basic
/
f
list
/
a
list-last
/
prefix-rec-02
nat-basic
/
c
nat-basic
/
a
list
/
c
nat
/
lez
list-last
/
prefix-nil
nat-basic
/
succ
nat
/
succ-01
nat-basic
/
less-zero
nat
/
pred-03
nat
/
elim-pred-c
nat
/
lels
nat-basic
/
s-04
nat-basic
/
oz
list-data
/
elim-add
nat-basic
/
l
list
/
len-05
list
/
e-01