| ⊦ s ⊆ dom st → dom(st | s) = s |
dom(st | s) ≠ s, s ⊆ dom st ⊦
| dom(st | s) ≠ s, s ⊆ dom st ⊦ |
dom st \ dom st \ s ≠ s, s ⊆ dom st ⊦
Used simplifier rules: restrict: ⊦ st | s = st \ (dom st \ s); dom-rem: ⊦ dom(st \ s) = dom st \ s;
| dom st \ dom st \ s ≠ s, s ⊆ dom st ⊦ |
⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2)
s ⊆ dom st, ∃ a. ¬(a ∈ dom st \ dom st \ s ↔ a ∈ s) ⊦
Used terms: s, dom st \ dom st \ s
| ⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) |
| s ⊆ dom st, ∃ a. ¬(a ∈ dom st \ dom st \ s ↔ a ∈ s) ⊦ |
¬(a ∈ dom st \ dom st \ s ↔ a ∈ s), s ⊆ dom st ⊦
| ¬(a ∈ dom st \ dom st \ s ↔ a ∈ s), s ⊆ dom st ⊦ |
⊦ a ∈ s1 \ s2 ↔ a ∈ s1 ∧ ¬ a ∈ s2
Used simplifier rules: Dom: ⊦ a ∈ dom st ↔ a ∈ st; sub-in: ⊦ a ∈ s ∧ s ⊆ s0 → a ∈ s0; (forward) from specification polyset-basic ne-01: ⊦ a ∈ s → s ≠ ∅; (forward) from specification polyset-basic ⊦ a ∈ s1 \ s2 ↔ a ∈ s1 ∧ ¬ a ∈ s2; (ws) Used terms: dom st \ s, dom st, a
| ⊦ a ∈ s1 \ s2 ↔ a ∈ s1 ∧ ¬ a ∈ s2 |
The following image shows the proof tree of sequent calculus. The proved goal is at the bottom. You can click on the nodes to view additional rules. See here for details on colors in a proof tree.